Re: ZetaTalk Gravity: Insight or Insanity?

Nancy Lieder <zetatalk@zetatalk.com> wrote in message news:<3B73F416.483181E0@zetatalk.com>...
> In Article <f4aad97f.0108092151.2de0d3eb@posting.google.com> Quantum Certainty wrote:
>> Thusly, I derived an equation that should describe the force
>> produced: Pd*Md*t*(Vg+Vo)=F where
>>     Pd=Particle Density ...
>>    Md=Mass Distance ...
>>        t=time ...
>>    Vg=velocity of Gravity particles ...
>>    Vo=Velocity of Object ...
>>       F=Force ...
>>
>> Newton's Law (HA) ...
>>      F=ma=Pd*m*t*(Vg+Vo)*G ...
>>      a=Pd*distance*G
> 
>     Excellent start, but you err in including velocity.
>     Although in the finite analysis this would be included,
>     in the gross comparison to Newton and what you have
>     termed HA, this does not apply.  Do you compute the
>     velocity of LIGHT when doing a computation on light
>     refraction on the surface of Earth, or light reflection
>     from Mars?  You do only when dealing with light
>     coming from great distances, as a factor of the distance,
>     but not when close at hand.  In this regard, treat gravity
>     particles as you do light particles, during your generation
>     of a human Repulsion Force formula.
>         ZetaTalk™
> 

I included velocity because Zetatalk states that "the outward streams
are propelled, with a force and at a SPEED (my emphasis) so much
greater than the downward drafts that this occurs over less of a
surface area and without engaging the mass of the object." Thus, I
concluded that speed was an important factor in calculating the force
exerted. So does the repulsion force travel faster than the attractive
force? Or do they both travel at a constant speed? How fast do they
travel compared with the speed of light?

Also, I visualize the force exerted by the repulsive force (per your
description ) as a bell curve--i.e. the force engages an object more
and more with distance thus exerting more force too a piont where the
force exerted falls off. Is the falling force due to the dimished
velocity of the repulsive particles, the dimished density (since they
are spread out over a larger region of space), or both?

Quantum Certainty